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884 Part VI: Measuring and Trading VolatiHty
To answer the question, one must create two equations in two unknowns, x and
y. The unknowns represent the quantities of options to be bought and sold, respec­
tively. The constants in the equations are taken from the table above.
The first equation represents gamma neutral:
0.045 X + 0.026 y = 0,
where
xis the number of April 50's in the spread and y is the number of April 60's. Note
that the constants in the equation are the gammas of the two calls involved.
The second equation represents the desired vega risk of making 2.5 points, or $250,
if the volatility decreases:
0.08 X + 0.06 y = - 2.5,
where
x and y are the same quantities as in the first equation, and the constants in this equa­
tion are the gammas of the options. Furthermore, note that the vega risk is negative,
since the spreader wants to profit if volatility decreases.
Solving the two equations in two unknowns by algebraic methods yields the fol­
lowing results:
Equations:
0.045 X + 0.026 y = 0
0.08 X + 0.06 Y = - 2.5
Solutions:
X = 104.80
y = -181.45
This means that one would buy 105 April 50 calls, since x being positive means that
the options would be bought. He would also sell 181 April 60 calls (y is negative,
which implies that the calls would be sold). This is nearly the same ratio determined
in the previous example. The quantities are slightly higher, since the vega here is
-$250 instead of the -$238 achieved in the previous example.
Finally, one would again determine the amount of stock to buy or sell to neu­
tralize the delta by computing the position delta:
Position delta = 105 x 0.47 - 181 x 0.17 = 18.58
Thus 1,858 shares of XYZ would be shorted to neutralize the position.